I can't figure out the formula for this problem, NO should cancel out.

To show water and NO as the product
I will take equation 1 as such and will multiply eq 2  with 3/2 and eq3 as such and then add them together
Final equation will be
8NH3 + 13O2 ---> 4NO + 4HNO3 + 10H2O
∆H = -905 -3/2(112)-138 = -1211kJ
Rxn is exothermic