One of my problems says to draw the Lewis Dot Structure for BeF2, but the formal charge is not zero if I put a double bond between F's and Be. I would do this to complete the octet for all, but does Be not have to have 8 e-? Because if that's the case, I can just put three lone pairs on each F and it would be fine, right?
Solution here
https://topblogtenz.com/beryllium-fluoride-bef2-lewis-structure-molecular-electron-geometry-bond-angle-hybridization/
Quote from: ann on October 05, 2022, 11:22:14 PM
One of my problems says to draw the Lewis Dot Structure for BeF2, but the formal charge is not zero if I put a double bond between F's and Be. I would do this to complete the octet for all, but does Be not have to have 8 e-? Because if that's the case, I can just put three lone pairs on each F and it would be fine, right?
In BeF
2, Be is not with octet and is electron deficient.
Be can give only two electrons for sharing so it can have only two covalent bonds. Fluorine never make a double bond and is always single bonded in its compounds.
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