from the information below determine the mass of substance that will be formed if 45.0 grams of substance A reacts with 23.0 grams of substance b. (assume that the reaction between a ans B goes to completion.)
A) Substance A is gray solid that consist of an alkaline earth metal and carbon (37.5% by mass). It reacts with substance B to produce substances C and D. Forty million trillion formula units of A have a mass of 4.6 milligrams.
B) 47.9 grams of substance B contains 5.36 grams of hydrogen and 42.5 grams of oxygen.
C) when 10.0 grams of C is burned in excess oxygen, 33.8 grams of carbon dioxide and 6.92 grams of water are produced. A mass spectrum of substance C shows a parent molecular ion with a mass-to-charge ratio of 26.
D) substance D is the hydroxide of the metal in substance A.
Here is the solution of the marathon problem
A
no of formula units = 40 X 10^6X10^12 (40 million trillion)
mass of the 40million trillion = 4.6mg = 4.6 X 10^-3g
no of formula units in one mole = 6.022 X 10^23
no of moles in 40 million trillion units = 40 X 10^6X10^12/6.022 X 10^23 = 6.642 XX10^-5
mass of 6.642 X 10^-5 moles = 4.6 X 10^-3 g
mass of one mole is = 4.6 X10^-3/ 6.642X10^-5 = 69.26 g
Amount of carbon = 37.5 X 69.26 /100 = 25.97g
mass of Metal in A in one mole = 69.26 – 25.97 = 43.3 g ( Ca metal )
no of moles of carbon = 25.97/12.0 = 2.2 ~ 2
metal in A is Ca and formula unit is CaC2
B
Moles of H in B = 5.36 g / 1.008 = 5.13 moles of H
Moles of O = 42.5 /16.00= 2.66 moles of O
H:O = 2 : 1
Hence B is H2O
C
Moles of Carbon = 33.8gCO2 X 12 .0g C /44g of CO2 X 1mole of C/ 12.0 g of C = 0.77 moles`
Moles of H = 6.92 g of water X 2.016 g of H/18.016 g of water X 1mole of H / 1.008 g of H = 0.77 moles Of H
C:H = 1:1
Molar mass of C is 26 (from molecular ion peak of mass spectra)
Empirical formula mass is 13.008 g
n = molar mass /empirical formula mass = 26/13.008 ~ 2
hence C is (CH)2 = C2H2
D
Since metal is Ca hence its hydroxide is Ca(OH)2
CaC2 + 2H2O --------> Ca(OH)2 + C2H2
A B C D
oh thank you it helped alot