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Chemistry Homework Help => CBSE XI and XII Chemistry => Topic started by: Pranjal Singh on August 13, 2020, 05:48:27 AM

Title: de Broglie's wavelength
Post by: Pranjal Singh on August 13, 2020, 05:48:27 AM
An electron in an H-atom in its ground state absorbs 1.5 times as much energy as the minimum required for its escape(13.6 eV)  from the atom. What is the wavelength of the emitted electron?
Title: Re: de Broglie's wavelength
Post by: uma on August 16, 2020, 05:22:01 AM
Energy absorbed by the electron is used in doing two things one, in overcoming the attractive forces with the nucleus and another as kinetic energy of emitted electron.(Photoelectric effect)
The energy needed to overcome the attractive forces is also called as binding energy or ionization energy of the electron which is given here is 13.6 electron volt .Total amount of energy absorbed by the electron is 1.5 times of 13.6 ev.Hence the  kinetic energy by which the electron is emitted is total absorbed  energy-13.6 .Now rest is mathematics you can convert this energy by using  Planck's equation into lambda.