QuoteThe rate of diffusion two gases A and B are in the ratio 1 : 4. If the ratio of their masses present In the mixture is 2 :3. The ratio of their mole fraction is : (9 1/3 = 2.08)
μA/μB=√(MB/MA)=1/4Taking square of both sides
MA = 16MBMole of A = 2x/MA= 2x/16MB
Moles of B = 3x/MB
Total moles = 2x/16MB + 3x/MB
= 50x /16MB
X
A=2x/16MB ∗ 16MB/50X=0.04
XA+ XB=1 Calculate X
B and take their ratio