specific heat problems

Started by joyjang, September 19, 2012, 03:24:06 AM

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joyjang

Calculate the number of kilocalories necessary to heat 250. g of water from 19.6 to 68.8 oC.

uma

use q = ms(tf-ti)=250 * 4.164(68.8-19.6)
Answer will be in Joules which we need to convert to kcal
1 kcal = 0.004184 J

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