mam, in this question I understand that delta G is greater than zero but why is it not at standard?Screenshot 2026-04-17 131446.png
In this question, we are discussing ΔGand not ΔG∘because the gases are mixed under non-standard conditions. Therefore, we must compare Qp with Kp. Since Q p>K p, the reaction mixture has excess products compared with equilibrium, so the reaction shifts toward the reactants. Hence, the forward reaction is non-spontaneous at that instant, and ΔG>0.