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question

You need to write down the balanced equation of KMnO4 with H2O2
KMnO4 is reduced to Mn ²⁺
And H2O2 is oxidized to O₂
If you look at the half reactions then in the reduction of one mole of MnO₄ ^- we need 5 electrons
In the oxidation of 1 mole of H₂O₂ to O₂ we get only two electrons.


5 electrons + MnO₄-  -------> Mn²⁺

H₂O₂ ---->  O₂ + 2 electrons

Multiply above equation by 2 and below equation by 5
This will equalize the number of electrons transferred and from here we can work out the mole ratio and you can check for every one mole MnO ₄ ^- we need 5 / 2 moles of H₂O₂

10 electrons + 2MnO₄-  -------> 2Mn²⁺

5H₂O₂ ---->  5O₂ + 10 electrons