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Laboratory chemistry => Chemistry Lab Help => Topic started by: joyjang on September 19, 2012, 03:24:06 AM

Title: specific heat problems
Post by: joyjang on September 19, 2012, 03:24:06 AM
Calculate the number of kilocalories necessary to heat 250. g of water from 19.6 to 68.8 oC.
Title: Re: calculaions for calorimeter on q needed
Post by: uma on August 03, 2019, 07:41:06 AM
use q = ms(tf-ti)=250 * 4.164(68.8-19.6)
Answer will be in Joules which we need to convert to kcal
1 kcal = 0.004184 J
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