Hello! I have a few questions related to NMR that I would love clarification on, thank you so much!

Hello! I have a few questions related to NMR that I would love clarification on, thank you so much!

Hello! I have a few questions related to NMR that I would love clarification on, thank you so much!


   

Hello! I have a few questions related to NMR that I would love clarification on, thank you so much!
 

Hello! I have a few questions related to NMR that I would love clarification on, thank you so much!

 Substances that donate H⁺ in water are Brønsted–Lowry acids, and substances that accept H⁺ are Brønsted–Lowry bases.
H₃PO₄ and H₂PO₄⁻ can both act as Brønsted–Lowry acids because each can donate a proton. However, H₃PO₄ is a stronger acid than H₂PO₄⁻ since it carries no negative charge and more readily donates H⁺.
I⁻ and Ba(OH)₂ act as bases.
I⁻ can accept a proton to form HI.
Ba(OH)₂ provides OH⁻ ions, which readily accept H⁺ to form water.
H₂PO₄⁻ is amphiprotic—it can also act as a base by accepting a proton to form H₃PO₄.

Hi Mam,

I was wondering how to identify the Bronsted Lowry Acids and Bases?

Thank you  for the help!

Your method is correct however the value is for two moles of C4H10.In the balanced equation it is 2 moles of butane on combustion gives −5756 kJ of energy.
You need to take this ratio-
 580 g * (1mol C₄H₁₀ / 58.12g  ) * (−5756 kJ / 2 moles C₄H₁₀)

Not sure why answer choice C is wrong given my work

 

To show water and NO as the product
I will take equation 1 as such and will multiply eq 2  with 3/2 and eq3 as such and then add them together
Final equation will be
8NH3 + 13O2 ---> 4NO + 4HNO3 + 10H2O
∆H = -905 -3/2(112)-138 = -1211kJ
Rxn is exothermic